In a equilateral triangle ABC , D is a point on side BC such that BD = 1/3 BC .Then prove that 9 AD^2 = 7AB^2
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AD2=AM2+DM2
&AB2=BM2+AM2
from 1
Ad2_dm2
&AB2=BM2+AM2
from 1
Ad2_dm2
Answered by
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the answer is as follows:
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