Math, asked by keshavmourya323, 4 months ago

In a
equilateral triangle of Side 3√3
Find the length of
the altitude
cm​

Answers

Answered by garima2412
4

Answer:

4.5cm

Step-by-step explanation:

REF.Image

Given

side of an equilateral triangle

ABC=3

3

cm

AB=BC−AC=3

3

cm

Let AD=h (altitude)

BD=

2

1

B (Altitude bisect the base)

BD=

2

1

.3

3

=3

3

/2 cm

AB

2

=AD

2

+BD

2

(3

3

)

2

=(h)

2

+(3

3

/2)

2

⇒27=h

2

+27/4

⇒h

2

=27−27/4

⇒h

2

=(4.27−27)/4

⇒h

2

=108−27/4

⇒h

2

=81/7

⇒h=

81/4

⇒h=9/2

⇒h=4.5cm

Hence, the length of the altitude h is 4.5 cm

Answered by Krystalverma
0

Answer:

Length of altitude is 4.5

Step-by-step explanation:

REF.Image

Given

side of an equilateral triangle

ABC=3

3

cm

AB=BC−AC=3

3

cm

Let AD=h (altitude)

BD=

2

1

B (Altitude bisect the base)

BD=

2

1

.3

3

=3

3

/2 cm

AB

2

=AD

2

+BD

2

(3

3

)

2

=(h)

2

+(3

3

/2)

2

⇒27=h

2

+27/4

⇒h

2

=27−27/4

⇒h

2

=(4.27−27)/4

⇒h

2

=108−27/4

⇒h

2

=81/7

⇒h=

81/4

⇒h=9/2

⇒h=4.5cm

Hence, the length of the altitude h is 4.5 cm

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