in a factory the production of bike was 40,000 in a particular year,which rose to 48,400 in two years. find the rate of growth per annum, if it was uniform during two years.
Answers
Answered by
168
48000 = 40000(1+r/100)^2 ( The formula is a(1+r/100)^n
(1+r/100)^2 = 484/400
(1+r/100)^2 = (22/20)^2
1 + r/100 = 22/20
r/100 = 22/20 - 1
= 1/10
r = 100/10
= 10.
The rate of growth per annum = 10%.
Hope this helps!
(1+r/100)^2 = 484/400
(1+r/100)^2 = (22/20)^2
1 + r/100 = 22/20
r/100 = 22/20 - 1
= 1/10
r = 100/10
= 10.
The rate of growth per annum = 10%.
Hope this helps!
Answered by
174
Hey friend!
Here the answer!!
please see attachment
HOPE it helped
Here the answer!!
please see attachment
HOPE it helped
Attachments:
Similar questions