Question

in a factory, there are 6 skilled workers and 4 unskilled workers. what is the probability that (a) worker selected a skilled worker, (b) the two workers selected are skilled? plz , plz answer​

Answer 1

total workers = 6+4=10

skilled worker =6

p(skilled person) = no of favourable outcome /total no of outcome

p(s)=6/10=3/5.

probability of skilled person=3/5

Answer 2

Answer:

Hence Probability  that worker selected a skilled worker is $\frac{6}{10}$ and Probability that the two workers selected are skilled is  $\frac{1}{3}$  

Step-by-step explanation:

Number of skilled workers = 6

Number of unskilled workers = 4

Total no. of workers = 6+4=10

(a) the probability that worker selected a skilled worker

Favorable event = skilled workers = 6

Total workers = 10

Probability  that worker selected a skilled worker=$\frac{6}{10}$

(b) the two workers selected are skilled

Favorable event = skilled workers = 6

Total workers = 10

Probability  that worker selected a skilled worker=$\frac{6}{10}$

Now Remaining skilled workers = 5

Remaining total workers = 9

Probability  that worker selected on second chance is a skilled worker=$\frac{5}{9}$

Probability that the two workers selected are skilled= $\frac{6}{10} \times \frac{5}{9}$

                                                                                      = $\frac{1}{3}$  

Hence Probability  that worker selected a skilled worker is $\frac{6}{10}$ and Probability that the two workers selected are skilled is  $\frac{1}{3}$