Question

In a fair coin we have an equal chance (50%) of either getting a head' or tail'. That is if we toss the coin a large number of times we would observe head approximately 50% of the time. Write a program to implement a biased coin toss where the chance of getting a head is 70% (and tail 30%). That is if we invoke the program 1000 times we should see the head randomly approximately 700 times.

Answer 1

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Answer 2

The python code for doing the required task is as follows:

from pylab import*

def cointoss(n):

   rv=random.random(0,1,size=n)

   for i in rv:

       if (rv[i]<=0.7):

           rv[i]='heads'

       else:

           rv[i]='tails'

   return rv

• The following code uses a random variable generator which gives us n random numbers between 0 to 1 .
• Making the coin biased is equivalent to making the random numbers less than 0.7 equal to heads and the rest equal to tails.
• If n is set to 1000 and the function cointoss is called , it will print an array containg 1000 heads and tails , where number of tails will be almost equal to 700.