In a fair,if 12 generators work for 6 hours a day,then deposited oil is finished in 7 days.If generators run for 4 hours a day for 9 days,then let us find how many generators can run with out remaining amount of oil
Answers
Let's first find the amount of oil that is deposited in one day by 12 generators working for 6 hours. Let the amount of oil deposited in one day be O:
12 generators * 6 hours/day = 72 generator-hours/day
O * 7 days = 72 generator-hours/day
O = 72/7 = 10.2857 (approximately)
So, the amount of oil deposited in one day by 12 generators working for 6 hours is approximately 10.2857.
Now let's find the amount of oil required to run the generators for 4 hours a day for 9 days. Let the amount of oil required for one generator to run for 4 hours be o:
1 generator * 4 hours/day = 4 generator-hours/day
o * 9 days * x generators = 4 generator-hours/day * 9 days * x generators
o * 9 * x = 36 * x
where x is the number of generators that can run without remaining oil.
So, the amount of oil required to run x generators for 4 hours a day for 9 days is 36x.
Since the amount of oil deposited in one day is approximately 10.2857, we can find the number of generators that can run for 9 days without remaining oil:
10.2857 * 7 days / (4 hours/day) * x generators = 36x
28.6x = 72.0
x = 2.52
Therefore, approximately 2 or 3 generators can run for 4 hours a day for 9 days without remaining oil.