Question

Please guys help me I need your help

Answer 1

$\huge \bold{ANSWER:-}$

____________________________

★ GIVEN :-

1) The ratio of two corresponding sides of two similar triangles is 1:3, then the ratio of their areas is

SOLUTION :-

let us consider two similar triangles Δ ABC Δ XYZ. the ratio of the area of Δ ABC/area of Δ XYZ = (1/3)² we know from the theorem(the ratio of the area of the both the triangles is proportional to square of the ratio of their respective corresponding sides. )

= 1/9

ANSWER :-

4) 1/9

_____________________________

★ GIVEN :-

2) D, E are midpoints of sides AB, AC of ∆ABC. If DE = 4cm then BC =

SOLUTIONS :-

DE=1/2BC

DE=1/2BC4=1/2BC

DE=1/2BC4=1/2BC4x2=BC

DE=1/2BC4=1/2BC4x2=BC8cm

ANSWER :-

3) 8 CM

_____________________________

★ GIVEN :-

3) if the side of an equilateral triangle it 8 cm then its area is ?

SOLUTION :-

area = 27.71

area = 27.7116√3 = 27.71

ANSWER :-

2) 16√3

_____________________________

★ GIVEN :-

4) The length of diagonal of a square is 5√2 cm, then its area is

SOLUTION :-

a = 25

ANSWER :-

2) 25

_____________________________

★ GIVEN :-

5) If the units and ten's digit of a two digit number ar 'y' and x' respectively. Then the number in a linear equation in two variables is

SOLUTION :-

10y +X

ANSWER :-

4) X + 10y

_____________________________

GIVEN :-

6) If the line y = px - 2 passes through (3.2) then p= ?

SOLUTION :-

y = px-2 = 2

px = 2+2

px = 2+2p(3) = 4

p = 4/3

ANSWER :-

$\bold{3) \frac{4}{3} }$

_____________________________

GIVEN :-

7) The point of intersection of the lines x 2 =0 and y + 6 = 0 is

SOLUTION :-

So, the point of intersection of the lines (i) and (ii) is (2, - 6).

ANSWER :-

4) 2, - 6

_____________★______________

Answer 2

Answer:

★ GIVEN :-

1) The ratio of two corresponding sides of two similar triangles is 1:3, then the ratio of their areas is

SOLUTION :-

let us consider two similar triangles Δ ABC Δ XYZ. the ratio of the area of Δ ABC/area of Δ XYZ = (1/3)² we know from the theorem(the ratio of the area of the both the triangles is proportional to square of the ratio of their respective corresponding sides. )

= 1/9

ANSWER :-

4) 1/9

_____________________________

★ GIVEN :-

2) D, E are midpoints of sides AB, AC of ∆ABC. If DE = 4cm then BC =

SOLUTIONS :-

DE=1/2BC

DE=1/2BC4=1/2BC

DE=1/2BC4=1/2BC4x2=BC

DE=1/2BC4=1/2BC4x2=BC8cm

ANSWER :-

3) 8 CM

_____________________________

★ GIVEN :-

3) if the side of an equilateral triangle it 8 cm then its area is ?

SOLUTION :-

area = 27.71

area = 27.7116√3 = 27.71

ANSWER :-

2) 16√3

_____________________________

★ GIVEN :-

4) The length of diagonal of a square is 5√2 cm, then its area is

SOLUTION :-

a = 25

ANSWER :-

2) 25

_____________________________

★ GIVEN :-

5) If the units and ten's digit of a two digit number ar 'y' and x' respectively. Then the number in a linear equation in two variables is

SOLUTION :-

10y +X

ANSWER :-

4) X + 10y

_____________________________

GIVEN :-

6) If the line y = px - 2 passes through (3.2) then p= ?

SOLUTION :-

y = px-2 = 2

px = 2+2

px = 2+2p(3) = 4

p = 4/3

ANSWER :-

\bold{3) \frac{4}{3} }3)

3

4

_____________________________

GIVEN :-

7) The point of intersection of the lines x 2 =0 and y + 6 = 0 is

SOLUTION :-

So, the point of intersection of the lines (i) and (ii) is (2, - 6).

ANSWER :-

4) 2, - 6

_____________★

Step-by-step explanation:

Hope it helps you✌️✌️