Question

In a family of 3 children find the probability of having at least 1 boy​

Answer 1

Answer:

1÷3

Step-by-step explanation:

1 boy in a family of three members

Answer 2

according to the above condition,

n(S) = { BBB,GGG,BBG,BGG,

GGB,GBB,BGB,GBG}

NOW,

AT LEAST OF 1 BOY,

n(B)= {BBB,BBG,BBG,BGG,GGB,,,

GBB,BGB,GBG}

n(B)= 7

probability,

$n( \frac{b}{s} ) = \frac{7}{8} \\ \\ \\ it \: will \: definetly \: help \: u \: .....$