Question

in a family of 3 children find the probability of having at least one boy with

Answer 1

probability of having at least 1 boy 2 by 3

Answer 2

s(BBB,BBG,BGG,BGB,GGG,GBB,GBG,GGB) n(s)=8
A(BBB,BBG,BGG,BGB,GBB,GBG,GGB)n(A)=7
n(p)=8
n(a)=7.