Question

in a family of 8 males and a few females ,the average monthly consumption per head is 10.8 kg. If the average monthly consumption per head be 15 kg in the case of males of 6 kg in case of females . find the no. of females in the family.
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Answer 1

Answer:

MINORS ARE 7

Step-by-step explanation:

LET NNO OFF MINORSBE X

THUS AVERAGE CONSUPTION = 15INTO8 PLUS6INTOX DIVIDED BY8 PLUS X = 10.8

X=7

MINORS ARE 7

Answer 2

Answer:

Required number of females are 9.

Step-by-step explanation:

Given, a family has 8 males and few females and the average monthly consumption per head is 10.8 kg

Let number of female be x.

So,total members in the family $= (8 + x)$

Total monthly food consumption by the family $10.8 \times (x + 8) \: kg$

It is also given that the average monthly consumption per head be 15 kg in the case of males of 6 kg in case of females.

So, total monthly food consumption by male $= 8 \times 15 = 120 \: kg$

and total monthly food consumption by female $= x \times 6 = 6x \: kg$

So total food consumption by all male and female in the family $= (120 + 6x) \: kg$

Now,

$10.8(x + 8) = 120 + 6x \\ 10.8x + 86.4 = 120 + 6x \\ 10.8x - 6x = 120 - 86.4 \\ 4.8x = 33.6 \\ x = \frac{33.6}{4.8} \\ x = 7$

Required number of females are 7

This is a problem of Average.

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