Question

Malic acid has formula HOOCH(OH)CH2COOH. Three moles of which will react with one mole of the malic acid
a. Sodium bicarbonate b. Sodium metal
c. Potassium hydroxide d. Ethanol in conc. H2SO

Answer 1

Answer:

Sodium bicarbonate and sodium hydroxide cannot exist together in the aqueous solution because they react with each other. Sodium bicarbonate acts like an acid and sodium hydroxide acts as a base. The products of the reaction are sodium carbonate and water.

NaHCO

3

+NaOH→Na

2

CO

3

+H

2

O

Similarly, sodium hydroxide and sodium dihydrogen phosphate react to form sodium phosphate and water.

NaH

2

PO

4

+2NaOH→Na

3

PO

4

+2H

2

O

Hence, option D is correct.