Math, asked by khushi02022010, 6 months ago

In a family of 8, the men eat on average 72kg of food and women eat on an average 50kg of food. The men and women are equal in number. A hungry woman named Neetu joined the family for dinner and the average consumption became 67.How much did Neetu eat (in kgs) ?

Answers

Answered by Anonymous

Answer:

= Rs. 11.5

As men and women are equal so , there are 4 women and 4 men so, total consumption will be 72×4 = 288(by men) and 50×4 = 200(by women)

Total consumption = 488.

But after including Neetu the average consumption for 9 people is given to be 67.So the total consumption will be 67×9 = 603. So, Neetu’s consumption will be = 603 – 488 = 115

Answered by Anonymous

Total weight of A + B + C = 84 x 3 = 252 kg

Total weight of A + B + C + D = 80 x 4 = 320 kg

∴ Weight of D = 320 - 252 = 68 kg

Given, E = D + 3 = (68 + 3) kg = 71 kg

Total weight of B + C + D + E = (79 x 4) kg = 316 kg

∴ Weight of B + C = 316 kg - 71 kg - 68 kg = 177 kg

Weight of A only = 320 kg - 177 kg - 68 kg = 75 kg

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In a family of 8, the men eat on average 72kg of food and women eat on an average 50kg of food. The men and women are equal in number. A hungry woman named Neetu joined the family for dinner and the average consumption became 67.How much did Neetu eat (in kgs) ?​

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In a family of 8, the men eat on average 72kg of food and women eat on an average 50kg of food. The men and women are equal in number. A hungry woman named Neetu joined the family for dinner and the average consumption became 67.How much did Neetu eat (in kgs) ?