Question

in a family of three children find the probability of having at least one boy

Answer 1

Answer:

Step-by-step explanation:

PROBABILITY = 7/8

Answer 2

Answer: 7/8

Step-by-step explanation:

n(s): GGG,GGB,GBG,GBB,BBB,BBG,BGB,BGG

Let E1 be the event of getting at least a boy.

n(E1) : 7(GGB,GBG,GBB,BBB,BBG,BGB,BGG)

P(E1): n(E1)/n(s)

         :7/8

Hope it helps!! :)

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