in a family , the father took one forth of the cake and he had 3 times as much as each of the other members had. find the total no. of family members
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let total cake be x
father took 1/4 of the cake
so father take = x / 4
so each member take = x / 12
let other members are m
so total cake will be ,
x/4 + mx /12 = x
x ( 1/4 +m/12) = x
1 /4 + m / 12 = 1
4m + 12 = 48
4m = 36
m = 9
so other members are 9
and total members including father are 10
father took 1/4 of the cake
so father take = x / 4
so each member take = x / 12
let other members are m
so total cake will be ,
x/4 + mx /12 = x
x ( 1/4 +m/12) = x
1 /4 + m / 12 = 1
4m + 12 = 48
4m = 36
m = 9
so other members are 9
and total members including father are 10
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