in a family there are 3 children.Find the probability that at least two children are boys
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Answered by
1
possible combination
{GGG,GBG,GBB,GGB,BBG,BGG,BGB,BBB}
So
number of combination having at least two boys=3
probability=3/8
{GGG,GBG,GBB,GGB,BBG,BGG,BGB,BBB}
So
number of combination having at least two boys=3
probability=3/8
Answered by
0
No of childern = 3
no of possible outcomes = 6 (3 childern x possible genders [ male / female ])
No of outcome = 2 boys / males
Required probability = 2 / 6
= 1/3 OR 33.33 % (1/3 x 100)
no of possible outcomes = 6 (3 childern x possible genders [ male / female ])
No of outcome = 2 boys / males
Required probability = 2 / 6
= 1/3 OR 33.33 % (1/3 x 100)
shukoor:
sorry dont refer to it
its not right!
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