Math, asked by rohit574810, 1 year ago

in a farm there are 20 animals and their food provision to last for 8 days.after 2 day 10 more animals join the farm.for how many dayswill the pprovision now​

Answers

Answered by tanishqrajput86
17

Answer: 4 days

Step-by-step explanation:-

After 2 days we are left with 6 days.

Now If 20 animals consume food in 6 days then 1 animal will consume it in 20*6 = 120 days.

But now we have 20+10 = 30 animals.

Now, If 1 animal consume it in 120 days then 30 animals will consume it in 120/30 = 4 days.

You should not apply normal unitary method here. I hope it's helpful.

Answered by Pulastya07
5

Answer:

4 days

Step-by-step explanation:

Total food they have = 20*8 = 160

Food consumed in first two days = 2*20= 40

Remaining food = 160-40 = 120

Number of animals present after second day = 20 + 10 = 30

Number of days the food will last = 120/30 = 4 days.

The food will last for 4 more days.

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