In a farm there are some cows and some boys. Total number of legs is 610 and total number of heads is 200. Find the number of boys.
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let total number of boys be x
total number of cow be y
By A.T.Q
x+y=200
y=200-x
again By A.T.Q
2x+4y=610...........i
putting the value of y in eq. i
2x+4 (200-x)=610
2x+800-4x=610
800-2x=610
2x=800-610
2x=190
x=190/2
x=95
I hope this helps u.
total number of cow be y
By A.T.Q
x+y=200
y=200-x
again By A.T.Q
2x+4y=610...........i
putting the value of y in eq. i
2x+4 (200-x)=610
2x+800-4x=610
800-2x=610
2x=800-610
2x=190
x=190/2
x=95
I hope this helps u.
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