Question

In a FCC lattice, anions (A) form FCC array while cations (B) occupy 50% of tetrahedral voids. The formula of the compound is

Answer 1

Answer:

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Answer 2

Given:

The anions (A) forms FCC.

The cations (B) occupies 50% of tetrahedral voids.

To Find:

The formula of the compound.

Calculation:

- Let the no of anions (A) = x

⇒ The no of tetrahedral voids = 2x

⇒ The no of cations (B) = 50 % of 2x

⇒ B = 50/100 × 2x = x

- So, the ratio of atoms of A to B = x:x = 1:1

⇒ The formula of the compound is AB.