In a FCC lattice, anions (A) form FCC array while cations (B) occupy 50% of tetrahedral voids. The formula of the compound is
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Given:
The anions (A) forms FCC.
The cations (B) occupies 50% of tetrahedral voids.
To Find:
The formula of the compound.
Calculation:
- Let the no of anions (A) = x
⇒ The no of tetrahedral voids = 2x
⇒ The no of cations (B) = 50 % of 2x
⇒ B = 50/100 × 2x = x
- So, the ratio of atoms of A to B = x:x = 1:1
⇒ The formula of the compound is AB.
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