In a field , if 50% of white walkers were ravens, then there would be 50% more ravens than white walkers. What percentage of the overall field is ravens
Answers
Given :- In a field , if 50% of white walkers were ravens, then there would be 50% more ravens than white walkers. What percentage of the overall field is ravens ?
Solution :-
Let us assume that, total ravens in the field are x and white walkers are y .
so,
→ when 50% of white walkers were ravens , they were = (y/2)
Then we can say that, rest 50% or half left were white walkers .
then,
→ Total white walkers = (y/2)
and,
→ Total ravens = [x + (y/2)]
now, it has been given that, in this case there would be 50% more ravens than white walkers.
A/q,
→ Total ravens = 150% of white walkers
→ [x + (y/2)] = (150/100) * (y/2)
→ x + (y/2) = (3y/4)
→ x = (3y/4) - (y/2)
→ x = (3y - 2y)/4
→ x = (y/4)
→ y = 4x .
then,
→ Overall ravens in the field = x * 100 / (x + y) = x * 100/(x + 4x) = x * 100 / 5x = 20% (Ans.)
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Given : if 50% of white walkers were ravens, then there would be 50% more ravens than white walkers.
To Find : What percentage of the overall field is ravens
Solution:
White walkers = A
ravens = B
50% of white walkers were ravens,
=> white walkers = A - (50/100)A = A/2
ravens = B + A/2
there would be 50% more ravens than white walkers
B + A/2 = (A/2) ( 1 + 50/100)
=> B + A/2 = (A/2)(3/2)
=> B + A/2 = 3A/4
=> B = 3A/4 - A/2
=> B = A/4
=> A = 4B
Total = A + B = 4B + B = 5B
ravens = B
percentage of the overall field is ravens = (B/5B) * 100 = 20 %
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