Question

in a figure AB||DE and AC||DF then the theorem suitable to prove that ∆ABC~∆DEF is ?​

Answer 1

Answer:

A-A THEOREM OF SIMILARITY

Step-by-step explanation:

because

In triangles ABC and DEF

I. angle ABC = angle DEF (AB||DE)

II. angle ACB = angle DFE (AC||DF)

Therefore triangle ABC ~ triangle DEF (A-A Rule of similarity)