in a figure ABCD is a trapezium in which parallel sides are a B is equal to 78 CM BC is equals to 52 cm and a non parallel sides a BC is equals to 30 cm and AD is equals to 28 cm find the area of the trapezium
Vishwas1111:
please help to find out the answer as it is very important for me
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Answered by
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complete the parallelogram AECD by drawing CE//DA meeting AB at E.
CN perpendicular to AB is drawn.
Here,
DC=AE=52cm
AD=CE=28cm
EB=(78-52)cm=26cm.
In ▲BEC,
s=26+28+30÷2
=84÷2
=42cm.
Area of ▲BEC= s(s-a)(s-b)(s-c)
→1/2×26×CN= put the value of s(s-a)(s-b)(s-c)
you will find the value of CN then u can find the area of trapezium.
Hope u understand and it helps u...ALL THE BEST
CN perpendicular to AB is drawn.
Here,
DC=AE=52cm
AD=CE=28cm
EB=(78-52)cm=26cm.
In ▲BEC,
s=26+28+30÷2
=84÷2
=42cm.
Area of ▲BEC= s(s-a)(s-b)(s-c)
→1/2×26×CN= put the value of s(s-a)(s-b)(s-c)
you will find the value of CN then u can find the area of trapezium.
Hope u understand and it helps u...ALL THE BEST
Answered by
1
at first divide the trapizium into a parallogram an a triangle by putting a point E on the longer parallel side such that AE = BC Nd then find the area of triangle by herons formulae and the parallogram and then add them both
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