In a figure ABCD is rhombus. If AB=10cm and daignol AC=12cm. Find the daignal of the angle BD
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Refer to the photo. It's just the use of the Pythagorean Theorem.
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AC = 12cm
So, 1/2AC = 1/2×12 = 6cm
To find the diagonal of BD , we use pythagorean theorem
= (h)² = (p)² + (b)²
= (CD)² = (OD)² + ( OC)²
= (10)² = (OD)² + (6)²
= 100 = (OD)² + 36
= 100- 36 = (OD)²
= 64 = (OD)²
= \/64 ( under root 64) = OD
= 8 = OD
So, diagonal of BD is
= OD × 2 = 8 × 2 = 16cm
I hope this answer is helpful for you.......
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