In a figure, lines PQ and RS intersect each other at point O. If ∠por ∶ ∠roq is 5 ∶ 15. Then, find the angle of ∠.soq║×║
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Answer:
∠POR + ∠ROQ = 180° (Linear pairs of lines)
Given, ∠POR ∶ ∠ROQ = 5: 15
Therefore, ∠POR =
5/20× 180° = 45°
Similarly, ∠ROQ =15/20× 180° = 135°
Now, ∠POS = ∠ROQ° = 135° (Vertically opposite)
and ∠SOQ = ∠POR = 45° (Vertically opposite)
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