Math, asked by nid60, 8 months ago

In a figure ray BA ll ray DE <c=50° and <d=100° ​

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Answered by BrokenMimi
16

• Draw a line XY passing through point C and parallel to line AB as shown in figure,

⇔we have, AB ll DE and AB ll XY

if two lines in a plane are parallel to a third line in the plane, then those two lines are parallel to each other.

DE ll XY

ˢ ˡˡ ˣʸ ˢ ᴿˢᴿˢ ᴿˢ c

then, EDC + YCD = 180°

( pairs of interior angles on the same side of transversal are supplementary )

⇒100⁰ + ∠YCD = 180⁰

⇒∠YCD = 180⁰ - 100⁰

∠YCD = 80⁰

• since, sum of all the angles on a straight line at a point is 180⁰ then,

⇒∠XCB + ∠BCD + ∠YCD = 180⁰

⇒∠XCB + 50⁰ + 80⁰ = 180⁰

⇒∠XCB + 130⁰ = 180⁰

⇒∠XCB = 180⁰ - 130⁰

⇒∠XCB = 50⁰

since, AB ll XY and BC is transversal intersecting them at B and C,

∠ABC + ∠XCB = 180⁰ ( ᵖᵃᶦʳˢ ᵒᶠ ᶦⁿᵗᵉʳᶦᵒʳ ᵃⁿᵍˡᵉˢ ᵒⁿ ᵗʰᵉ ˢᵃᵐᵉ ˢᶦᵈᵉ ᵒᶠ ᵗʳᵃⁿˢᵛᵉʳˢᵃˡ ᵃʳᵉ ˢᵘᵖᵖˡᵉᵐᵉⁿᵗᵃʳʸ)

⇒∠ABC + 50⁰ = 180⁰

→ ∠ABC = 130

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