In a first order reaction, on plotting a graph between t2 and concentration of reactant
(1) A curve is obtained
(2) A straight line is obtained having slope 45°
(3) A straight line is obtained having slope 60°
(4) A straight line parallel to the concentration axis
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ANSWER
The integrated rate law for the first order reaction is k=
t
2.303
log
a−x
a
.
This equation can be rearranged as log
a
a−x
=
2.303
kt
+0. It is the form of straight line y=mx+c.
Hence, in a first order reaction, when log[
(a−x)
a
] is plotted against time, the graph obtained is a straight line having the slope
2.303
k
.
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