Question

In a first order reaction, reactant concentration C varies with time t as *

Answer 1

Answer:

The correct answer is log C decreased linearly with t.

Explanation:

From the above question,

They have given :

In a first order reaction, reactant concentration C varies with time t as *

   $\frac{k.t}{2.303}$  = log [$C_{0}$] - log [C]

C(t) = concentration C (C_0) $e^{(-kt)}$

where C_0 (concentration C) is the initial concentration of the reactant and k is the rate constant for the reaction.

This equation describes a first order reaction, where the rate of the reaction is proportional to the concentration of the reactant.

The rate constant k determines how quickly the reactant concentration decreases over time. As time passes, the reactant concentration is multiplied by a factor of $e^{(-kt)}$.

Which decreases exponentially with time. This means that the reactant concentration decreases more quickly over time as the reaction proceeds.

log [C]  = log [$C_{0}$] -  $\frac{k.t}{2.303}$  

Hence, The correct answer is log C decreased linearly with t.

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