in a flight for 3000km an aircraft was slowed down due to bad whather.its avg speed for the trip was reduced by 100 km/h and time of flight increased by 1 hr .find the org.duration of flight . plz just give me the equation formed and tell me how it was formed
Answers
Answered by
4
let x is the speed of aircraft and t is org.duration of flight.
we know
time =distance/speed
now according to question
3000/x=y ---------------(1)
3000/(x-100)=y+1 ------------(2)
now solve this equation and find x and y
subtracting (2)-(1)
3000 {1/(x-100)-1/x}=1
3000 x 100=x^2-100x
x^2-100x+300000=0
x=600 km/h
hence y=5hours
hence org. duration is 5hours
we know
time =distance/speed
now according to question
3000/x=y ---------------(1)
3000/(x-100)=y+1 ------------(2)
now solve this equation and find x and y
subtracting (2)-(1)
3000 {1/(x-100)-1/x}=1
3000 x 100=x^2-100x
x^2-100x+300000=0
x=600 km/h
hence y=5hours
hence org. duration is 5hours
abhi178:
please mark as brainliest
Similar questions