In a flight of 1400km, an aircraft was slowed down due to bad weather. Its average speed is reduced by 50 km/h and time increased by 30 minutes. Find the original duration of the flight
Answers
Let the duration of the flight be x hours.
It is given that the average speed for the trip was reduced by 200 km/hr and the time of flight increased by 30 minutes, therefore, we have:
⇒x=− 2 3 ,x=1
Ignoring the negative values, we have x=1.
Hence, the duration of the flight is 1 hour.
Answer:
answer
Step-by-step explanation:
Total distance given=6000km
Let
′
t
′
be the original duration of flight
Thus, the original speed =
t
6000
The speed for the trip was reduced by 400km/hr and time increased by 30 minutes
Thus,new speed=
t+
2
1
6000
Difference in speed=400km/hr
t
6000
−
t+
2
1
6000
=400
t(t+
2
1
)
6000(t+
2
1
)
−
t(t+
2
1
)
6000t
=400
3000=400t[t+
2
1
]
400t
2
+200t=3000
400t
2
+200t−3000=0
2t
2
+t−15=0
2t
2
+6t−5t−15=0
2t(t+3)−5(t+3)=0
(2t−5)(t+3)=0
t=
2
5
or t=−3
Time cannot be negative
t=
2
5
hour=60×
2
5
=150min
original duration of flight = 150min