x³-y³ using identity
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Answer:
x^3-y^3= (x-y)^3+3xy(x-y)
Hope that helps you ✌
Answered by
1
(x - y)^3 = x^3 - y^3 - 3xy(x - y)
=> x^3 - y^3 = (x - y)^3 + 3xy(x - y)
= (x - y)((x - y)^2 + 3xy)
= (x - y)(x^2 + y^2 + xy)
=> x^3 - y^3 = (x - y)^3 + 3xy(x - y)
= (x - y)((x - y)^2 + 3xy)
= (x - y)(x^2 + y^2 + xy)
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