Question

In a flood affected area, the volunteers of NSS erected a conical tent made of tarpaulin. The vertical
height of the conical tent is 8 m and the base diameter is 12 m. If the width of tarpaulin cloth is 3 m,
then find the length of the tarpaulin cloth used, assuming that extra tarpaulin cloth of length 120 cm
was used for stitching margins and wastage in cutting

Answer 1

Given :-

• Height of conical tent = 8m .
• Base diameter = 12 m.
• width of tarpaulin cloth = 3 m.
• Tarpaulin cloth used for stitching margins and wastage in cutting = 120 cm.

To Find :-

• The length of the tarpaulin cloth used .

Solution :-

we know that,

• Slant height of cone = √[Radius² + Height²]
• CSA of cone = π * radius * slant height .
• Radius = (Diameter/2) .

so,

→ Radius of conical tent = 12/2 = 6m .

then,

→ Slant height of cone = √(6² + 8²) = √(36 + 64) = √(100) = 10m .

therefore,

→ CSA of conical tent = 3.14 * 6 * 10 = 188.4 m².

hence,

→ Area of Tarpaulin cloth = width * length

→ 188.4 = 3 * length

→ Length = (188.4/3) = 62.8 m.

now, given that, 120 cm of length was used for stitching margins and wastage in cutting.

∴

→ The length of the tarpaulin cloth = 62.8 + 1.2 = 64 m. (Ans.)

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