Question

In a fort, 300 men had provisions for 90 days. After 20 days, 50 men left the fort. How long would the food last at the same rate?​

Answer 1

Answer:

total the sum of 20,50 and 90 then subtract the total sum by 300 the answer will be 140

Answer 2

Given:

300 men had provisions for 90 days.50 men left after 20 days.

To Find:

Duration for which 20 the food lasted.

Solution:

• The remaining food is sufficient for 300 men for (90-20)days=70 days
• Remaining number of men=(300-50)=250

• Let,the remaining food be sufficient for 250 men for x days.Then we have

     For, 300 men food is for 70 days

     and,250 men is for x days

     Clearly,less men will have food for more days

     So, it is a case of inverse proportion.

     ∴$300\times 70=250\times x$

     ⇒$x=\dfrac{300\times 70}{250}$=84

• ∴The required number of days=84