Question

In a fraction, if numerator is increased by 40 % and denominator is increased by 80 % then the resultant fraction is 3/5, what is the original is the new fraction?

Answer 1

let the friction is a/b
(a*140/100)/(b*180/100)=3/5
14a/18b =3/5
a/b=54/70
=27/35

Answer 2

Answer:

The original fraction is $\frac{27}{35}$

Step-by-step explanation:

Let the numerator be x

Let the denominator be y

Fraction = $\frac{x}{y}$

Numerator is increased by 40 %

Numerator = $x+\frac{40}{100}x= x+0.4x= 1.4x$

Denominator is increased by 80 %

Denominator = $x+\frac{80}{100}y= y+0.8y= 1.8y$

New fraction = $\frac{1.4x}{1.8y}$

We are given that the resultant fraction is 3/5,

So, $\frac{1.4x}{1.8y}=\frac{3}{5}$

$\frac{14x}{18y}=\frac{3}{5}$

$\frac{7x}{9y}=\frac{3}{5}$

$\frac{x}{y}=\frac{27}{35}$

Hence the original fraction is $\frac{27}{35}$