Math, asked by ritikgrover693, 11 months ago

In an year n, the 320th day of the year isthursday. In the year n+1, the 206th day ofthe year is also a thursday. What is the168th day in the year n-1?

Answers

Answered by shashank567
5
friday..If the Nth year is a non-leap year, then 320th day of year N to 206th day of year N+1 is [(365
– 320) + 206] = 251 days i.e. 35 weeks + 6 days. But this will not make the two days to be
Thursday.
Thus, the Nth year has to be a leap year. In this case 320th day of year N to 206th day of year
N+1 is [(366 – 320) + 206) = 252 days i.e. 36 weeks. Hence both days will be same day of the
week i.e. Thursday as given by the data.

168th day of N-1 year to 320th day of N year is [(365 – 168) + 320) = 517 days i.e. 73 weeks +
6 days. Thus, if the 320th day is Thursday, then the 168th day of year will be Friday, option
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