In a fraction numerator =2 less than the denominator. If 1 added to both numerator and denominator the fraction =2/3. Find the fraction
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Answer:
Step-by-step explanation:
Let the numerator be x and denominator be (x + 2)
So x +1 / x + 2 + 1= 2/3
=> x + 1 /x + 3 = 2/3
=> 3x + 3 = 2x + 6
=> x = 3
So the required fraction is 3/5
Answered by
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let debominator be 'x' and numerator be 'x-2'.
when 1 is added to both the numerator and denominator the fraction is, x-2+1/x+1
x-2+1/x+1=2/3
x-1/x+1=2/3
3(x-1)=2(x+1)
3x-3=2x+2
3x-2x=2+3
x=5
Therefore fraction x-2/x= 5-2/5=3/5
when 1 is added to both the numerator and denominator the fraction is, x-2+1/x+1
x-2+1/x+1=2/3
x-1/x+1=2/3
3(x-1)=2(x+1)
3x-3=2x+2
3x-2x=2+3
x=5
Therefore fraction x-2/x= 5-2/5=3/5
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