In a fraction, twice the numerator is 2 more than the denominator. If 3 is added the numerator and denominator. The new fraction will be 2/3...find the orginal fraction.
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Answered by
5
Let the numerator be x
Denominator = 2x − 2
Therefore the fraction = x/2x − 2
Given when 3 is added to both the numerator and denominator, the fraction becomes 2/3.
Hence (x + 3)/(2x − 2 + 3) = 2/3
⇒ (x + 3)/(2x + 1) = 2/3
⇒ 3x + 9 = 4x + 2
⇒ x = 7
Therefore the fraction is 7/12.
Give me brainliest please.
Denominator = 2x − 2
Therefore the fraction = x/2x − 2
Given when 3 is added to both the numerator and denominator, the fraction becomes 2/3.
Hence (x + 3)/(2x − 2 + 3) = 2/3
⇒ (x + 3)/(2x + 1) = 2/3
⇒ 3x + 9 = 4x + 2
⇒ x = 7
Therefore the fraction is 7/12.
Give me brainliest please.
Answered by
8
In a fraction, twice the numerator is 2 more than the denominator
let numerator be x
denominator = 2x - 2
so fraction = x/2x - 2
now,
If 3 is added the numerator and denominator. The new fraction will be 2/3
so
x +3/2x - 2 +3 = 2/3
x +3 /2x +1 = 2/3
3(x+3) = 2(2x +1)
3x +9 = 4x +2
9-2 = 4x - 3x
x = 7
now
denominator = 2x - 2
= 2*7 - 2 = 14 - 2
=12
hence the fraction is 7/12
:)
let numerator be x
denominator = 2x - 2
so fraction = x/2x - 2
now,
If 3 is added the numerator and denominator. The new fraction will be 2/3
so
x +3/2x - 2 +3 = 2/3
x +3 /2x +1 = 2/3
3(x+3) = 2(2x +1)
3x +9 = 4x +2
9-2 = 4x - 3x
x = 7
now
denominator = 2x - 2
= 2*7 - 2 = 14 - 2
=12
hence the fraction is 7/12
:)
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