Question

In a frequency distribution, the class mark of a class interval 84
class width is 8. Find the lower limit of that class interval.
किसी बारंबारता बंटन में, एक वर्ग अंतराल का वर्ग-चिन्ह 84 है तथा वर्ग-माप
इस वर्ग अंतराल की निम्न सीमा ज्ञात कीजिए।
।​

Answer 1

Answer:

let lower limit= x

upper limit = x+8

so, upper limit + lower limit/2= class mark

x+8+x/2=84

so x=80

Ans:80

Answer 2

Step-by-step explanation:

Given that:In a frequency distribution the class mark of a class interval is 84 and the class width is 8 .

To find:find the lower limit of class interval

Solution:

We know that class mark is given by

$\boxed{x_i = \frac{lower \: class \: limit + upper \: class \: limit}{2}}$

in the question class mark = 84

Let the lower class limit is x,

then upper class will be x+8

(Because width f class is 8)

Put these values

$84 = \frac{x + x + 8}{2} \\ \\ 168 = 2x + 8 \\ \\ 160 - 4 = 2x \\ \\ 2x = 160 \\ \\ x = \frac{160}{2} \\\\ x = 80$

Thus, class interval is 80-88.

Lower class limit is 80.

Hope it helps you.