Question

in a frequency distribution the mid value of a class is 10 and the widhth of the class is 6 the lower limit of the class is​

Answer 1

Let x and y be the upper and lower class limit in a frequency distribution.

Now, mid value of a class (x + y )/2=10 [given]

⇒ x + y = 20 …(i)

Also, given that, width of class x- y = 6 …(ii)

On adding Eqs. (i) and (ii), we get

2x =20+ 6

⇒ 2x =26 ⇒ x = 13

On putting x = 13 in Eq. (i), we get

13+y = 20 ⇒ y = 7

Hence, the lower limit of the class is 7

Answer 2

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