Question

In a frequency distribution, the mid value of a class is 75 and the lower limit of the class is 69, then the upper

limit of the class is​

Answer 1

Answer:

The answer is 81.

Step-by-step explanation:

Mid value=Lower limit+upper limit÷2

75=69+x/2

150=69+x

x=81.

Answer 2

SOLUTION

GIVEN

In a frequency distribution

• The mid value of a class is 75

• The lower limit of the class is 69

TO DETERMINE

The upper limit of the class

CONCEPT TO BE IMPLEMENTED

CLASS INTERVAL

When the number of sample values are large in number and are in wide range, then the whole data is divided in a number of several groups according to the size of the sample. Each of these groups, made as above, is known as class interval

CLASS LENGTH

Length of the class interval of an class is defined to be the difference between the lower and upper class boundaries ( not class limits) of that particular class interval.

Class length = Upper Class boundary - Lower class boundary

CLASS FREQUENCY

The number of observed values falling within a class is called the frequency of that class

CLASS MARK

For any grouped frequency table with class intervals, the middle value of the class limits or the class boundaries of any class is called class mark of the class

EVALUATION

Here it is given that In a frequency distribution, the mid value of a class is 75 and the lower limit of the class is 69

Let the upper limit of the class = x

So by the given condition

$\displaystyle \sf{ \frac{x + 69}{2} = 75}$

$\displaystyle \sf{ \implies x + 69 = 150}$

$\displaystyle \sf{ \implies x = 150 - 69}$

$\displaystyle \sf{ \implies x = 81}$

FINAL ANSWER

∴ The upper limit of the class = 81

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