Question

In a frequency distribution, the mid value of of the class is 12 and width is 6, find lower limit of the class.

1 point


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Answer 1

Answer:

answer is 18

ithinkso..

Answer 2

Answer :- 9 Bcoz

Class mark = Upper limit+Lower limit/2

12=Upper limit + Lower limit /2

Cross multiplication

Upper limit + Lower limit= 24

Class width = Upper limit - Lower limit

6= Upper limit - Lower limit

Subtraction

Upper limit + Lower limit = 24

Upper limit - Lower limit = 6

2 Lower limit =18

Lower limit =18/2

Lower limit =2