Question

In a full wave bridge rectifier, the transformer secondary voltage is 50 sinot The forward

resistance of each diode is 500 and the load resistance is 5000 Calculate DC output voltage, 10

Ripple factor, Efficiency of rectification and PIV across non conducting diodes​

Answer 1

Answer:

40% efficiency of rectification does not mean that 60% of power is lost in the rectifier circuit. In fact, a crystal diode consumes little power due to its small internal resistance. The 100 W a.c. power is contained as 50 watts in positive half-cycles and 50 watts in negative half-cycles. The 50 watts in the negative half-cycles are not supplied at all. Only 50 watts in the positive half-cycles are converted into 40 watts.