Physics, asked by mtanushree, 9 months ago

in a full-wave rectification circuit the d c load current equals 1amp. how much d c current is carried by each diode

Answers

Answered by samantasuman799
0

Answer:

in a full-wave rectification circuit the d c load current equals 1amp. how much d c current is carried by each diode

Answered by sourasghotekar123
0

Answer:

1 amp

Explanation:

  • There are two diodes in a full wave rectifier, but only one conducts at once. The transformer centre tap supplying the rectifier is where the return path leads.
  • According to Kirchhoff's Law, the diode will experience the same 1 amp current as the load is experiencing.
  • Four diodes make up a full wave bridge wave rectifier. One diode is in the forward path to the load during one half of the AC cycle, and the other is in the return path.
  • According to Kirchhoff, each will see 1 amp. The other two diodes pass the current when the other half of the cycle happens, and you got it—both diodes detect the 1 amp current—one detects it going in and the other seeing it going out.

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