Question

In a game of chance, a spinning arrow comes to rest at one of the numbers
1.2.3,4,5,6,7,8.
All these are equally likely outcomes.
Find the probability that it will rest at
2
(1) 8.
(2) an odd number.
(3) a number greater than 2.
(4) a number less than 9.​

Answer 1

Answer:

1]1/8

2]4/8=1/2

3]6/8=3/4

4] 1 as all the numbers are less than 9

Answer 2

PROBABILITY=(number of possible outcomes of the event/number of total possible outcomes)

In a game of chance ,a spinning arrow comes to rest at one of the numbers 1,2,3,4,5,6,7,8 and it is also given that all are equally likely outcomes

Let A be the event (getting number 2),B be the event (getting number 8), C be the event (getting a number greater than 2) and D be the event (getting a number less than 9).

Possible outcomes are 1,2,3,4,5,6,7,8

Total number of possible outcomes=8

Possible outcomes for event A is 2

No. of outcomes for event A=1

1) Probability (A)=1/8

Possible outcomes for event B is 8

No.of outcomes for event B=1

2) Probability (B)=1/8

Possible outcomes for event C are 3,4,5,6,7,8

No.of outcomes for event C=6

3) Probability (C)=6/8=3/4

Possible outcomes for event D are 1,2,3,4,5,6,7,8

No.of outcomes for event D=8

4) Probability (D)=8/8=1

HOPE THIS WILL HELP YOU