in a given figur find the length x
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x= a^2+b^2=c^2
=8^2+b^2=17^2
=64+b^2=289
=b^2=289-64
=b^2=225
=b=15
therefore x is 15cm
=8^2+b^2=17^2
=64+b^2=289
=b^2=289-64
=b^2=225
=b=15
therefore x is 15cm
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Tanya107:
i think ur ans. is wrong
pls check it again
yes that's why i again did it
i took 10 instead of 8
yaa
i again did it have u seen
yaa
Answered by
1
In triangle PRS
(PS)^2=(RS)^2+(PR)^2 {using pythagorus theorem}
100=36+(PR)^2
(PR)^2=64
PR=8
In triangle PQR
(PQ)^2=(PR)^2+(QR)^2 {using pythagorus theorem}
289=64+x^2
x^2=225
x=15
Answer is 15...hope this will help u..
(PS)^2=(RS)^2+(PR)^2 {using pythagorus theorem}
100=36+(PR)^2
(PR)^2=64
PR=8
In triangle PQR
(PQ)^2=(PR)^2+(QR)^2 {using pythagorus theorem}
289=64+x^2
x^2=225
x=15
Answer is 15...hope this will help u..
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