Question

in a given figure side BC of triangle ABC has been produced to D line she is parallel to be a if angle abc is 70 and angle BAC is 40 find triangle abc angle ACD angle ACD​

Answer 1

In triangle ABC

Given:-angleBAC=40,angleABC=70.

To find:-AngleACD

Solution:-In triangle ABC

TriangleABC=

=angleA+angleB+angleC=180(aspt)

=40+70+angleC=180

=110+angleC=180

=angleC=180-110

=anglec=70

AngleACD=

=AngleABC+AngleACD=180(aspt)

=70+AngleACD=180

=angleACD=180-70

=angleACD=110

HENCE PROVED