Question

in a given figure ,ST // RQ,PS=3cm. and SR=4cm.find the ratio of the area of ∆PST to the area of ∆ PRQ

Answer 1

GIVEN PS=3CM
SR=4CM
PS/SR=PT/TQ=3/4
PS/PR[SQUARE IT]
3/7[SQUARE]=9/49

Answer 2

Answer:

9:49

Step-by-step explanation:

Given

ST || RQ

PS= 3 cm

SR = 4cm

Proof :--

ar(∆PST) /ar(∆PRQ) = (PS)²/(PR)²

ar(∆PST) /ar(∆PRQ) = 3²/(PS+SR)²

ar(∆PST) /ar(∆PRQ) = 9/(3+4)²= 9/7² = 9/49

Hence, the required ratio ar(∆PST) :ar(∆PRQ) = 9:49