Question

In a given figure we have PQ=SR and PR=SQ. Prove that
1. ∆PQR cogruent to ∆SRQ
2.angle PQR =angleSRQ

Answer 1

Answer:

In triangle PQR and STQ

PQ=SR (given)

PR=SQ

QR=QR(common)

so, PQR CONGURENT TO STQ

ANGLE PQR = ANGLE SRQ (BY CPCT)

Answer 2

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$answer$

In △PQR and △SRQ,

PQ=SR(Given)

QR=QR(Common)

PR=SQ(Given)

By SSS property,

△PQR≅△SRQ

Hence proved.

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$thanks$