Question

In a given sample of NH3 (ammonia) 9 gm of Hydrogen and 42 gm of Nitrogen are present. In another sample 5 gm of hydrogen is present along with Nitrogen. Calculate the amount of Nitrogen in the second sample?

Answer 1

Explanation:

9:42 = 5:x (conservation of mass)

x = 42 × 5 / 9 = 23.333

hope it helps please mark me as brainliest