Question

In a given sequence last term is 96, first term is 12 and d is 4 then
find number of terms.​

Answer 1

Answer:

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Answer 2

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Question : In a given sequence last term is 96 ,first term is 12 and d is 4 then find number of terms.

Given :

•last term =96

•first term =12

•d=4

$\: \: \underline \green{ \boxed{\bf { \: answer}}}$

$\: \: \implies \bf{tn = a + (n - 1)d}$

$\: \: \implies \tt{96 = 12 + (n - 1)4}$

$\: \: \implies \tt{96 - 12 = (n - 1)4}$

$\: \: \implies \tt{84 = 4n - 4}$

$\: \: \implies \tt{84 - 4n + 4 = 0}$

$\: \: \implies \tt{no. \: of \: terms \: = \frac{88}{4} = 22}$

$\: \pink \bigstar \underline{ \boxed{ \tt{number \: of \: terms \: will \: be \: 22}}}$