Question

In a given slide callipers 10 division of its vernier coincides with its 9 main scale divisions. If one main scale division is equal to 0.5 mm then find its least count.

Answer 1

I hope that you got your required answer.
Please mark my answer brainliest.

Answer 2

Answer:

Value of one main scale division is 1 mm

10 div of vernier scale =9 mm.

1 div of vernier scale =9/10 mm.

Least count =L.C.= Value of one main scale division $$–$$ Value of one vernier scale division

$$L.C = $$ 1− 10/9

=1 mm−0.9 mm=0.1 mm=0.01 cm