Question

In a go the fourth term is 48 and the eighth term is 768 find the tenth term

Answer 1

Step-by-step explanation:

a4= a+ 3d = 48 (1)

a8= a+7d = 768 (2)

(2) - (1)

a + 7d = 768

a + 3d = 48

- - -

4d = 720

d = 180

a+ 3(180) = 48

a = 48- 560

a= - 512

a10 = a+ 9d

= 1620 -512

= 1108

Answer 2

Answer:

1128

Step-by-step explanation:

a+3d=48---------(1)

a+7d=768--------(2)

From equation (1) & (2) we get,

a+3d=48

a+7d=768

- - -

-----------------

-4d= -720

So, d=180

substituting value of 'd' in equation (1)

a+3d=48

a+3(180)=48

a=48-540

a=-492

Now, tenth term will be a+9d------- (3)

Putting value of 'a' and 'd' in equation (3)

(-492)+[9×(180)]

=(-492)+(1620)

=1128 Ans!!!!!!

Hope u liked the answer !!!!!

Mark me as branliest......